Asked by joe
A body is in equilibrum when three forces act on it.Two of the forces are F1 of magnitude 8Newtons acting due east and F2 which is 5Newtons acting 060. find the magnitude and direction of the third force.
Answers
Answered by
Henry
F1+F2+F3 = 0. F3 = -(F1+F2),
F3 = -(8N[0o]+5N.[60o]),
F3 = -((8+5*Cos60) + 5*sin60),
F3 = -10.5 - 4.33i = 11.4N[20.9o]
S. of W.
F3 = -(8N[0o]+5N.[60o]),
F3 = -((8+5*Cos60) + 5*sin60),
F3 = -10.5 - 4.33i = 11.4N[20.9o]
S. of W.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.