A body is in equilibrum when three forces act on it.Two of the forces are F1 of magnitude 8Newtons acting due east and F2 which is 5Newtons acting 060. find the magnitude and direction of the third force.

Answer 1

F1+F2+F3 = 0. F3 = -(F1+F2),
F3 = -(8N[0o]+5N.[60o]),
F3 = -((8+5*Cos60) + 5*sin60),
F3 = -10.5 - 4.33i = 11.4N[20.9o]
S. of W.