Asked by Kiki

What is final temperature of a 88 gram sample symbol of water at 295 k that absorbs 1250 Joules of heat ?

8 years ago

Answered by DrBob222

1250 J = mass H2O x specific heat x (Tfinal-Tinitial)
Solve for Tf.

8 years ago

Answered by Kiki

Thank you ! Do I have to K to C right ?

8 years ago

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