Asked by Michael
Integral from 1 to 3 of ( 19 + 2x - 20x ) dx
thanks
thanks
Answers
Answered by
Michael
EDIT:
that 20x is really 20x^3
that 20x is really 20x^3
Answered by
Damon
separate it into three integrals
19 dx --> 19 x ---> )19*3 - 19*1
2x^3 dx --> (1/2)x^4--> .5(27-1)
-20xdx--> -10x^2-->10(1-9)
19 dx --> 19 x ---> )19*3 - 19*1
2x^3 dx --> (1/2)x^4--> .5(27-1)
-20xdx--> -10x^2-->10(1-9)
Answered by
Help
Ok, first you integrate the problem so it equals 19x + x^2 - 5x^4
Next I'll write this out then show you. You then plug in x = 3 to this equation and then plug in x = 1
Subtract the equation of x = 1 from the equation x = 3.
(19(3) - (3)^2 - 5(3)^4) - (19(1) - (1)^2 - 5(1)^4) = -354
Next I'll write this out then show you. You then plug in x = 3 to this equation and then plug in x = 1
Subtract the equation of x = 1 from the equation x = 3.
(19(3) - (3)^2 - 5(3)^4) - (19(1) - (1)^2 - 5(1)^4) = -354
Answered by
Damon
2x^3 dx --> (1/2)x^4--> .5(27-1)
should be
20x^3 dx --> (10/2)x^4--> 5(81-1)
should be
20x^3 dx --> (10/2)x^4--> 5(81-1)
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