Integral from 1 to 3 of ( 19 + 2x - 20x ) dx

Question

thanks

Answer 1

EDIT:

that 20x is really 20x^3

Answer 2

separate it into three integrals
19 dx --> 19 x ---> )19*3 - 19*1
2x^3 dx --> (1/2)x^4--> .5(27-1)
-20xdx--> -10x^2-->10(1-9)

Answer 3

Ok, first you integrate the problem so it equals 19x + x^2 - 5x^4

Next I'll write this out then show you. You then plug in x = 3 to this equation and then plug in x = 1

Subtract the equation of x = 1 from the equation x = 3.

(19(3) - (3)^2 - 5(3)^4) - (19(1) - (1)^2 - 5(1)^4) = -354

Answer 4

2x^3 dx --> (1/2)x^4--> .5(27-1)
should be
20x^3 dx --> (10/2)x^4--> 5(81-1)