Asked by Alyssa
Find the derivative.
y=e^8x/[e^(8x)+9]
y' =
The answer I have is 8e^8x/[(e^8x+9)^2] but it marked it incorrect..
y=e^8x/[e^(8x)+9]
y' =
The answer I have is 8e^8x/[(e^8x+9)^2] but it marked it incorrect..
Answers
Answered by
practising and need help
okay here
set u=e^(8x)
v=(e^(8x)+9)
du/dx=8e^(8x)
dv/dx=8e^8x
dy/dx=[(e^8x+9)8e^8x-e^8x(8e^8x)]/(e^8x+9)^2
dy/dx=(8e^64x+72e^8x-8e^64x]/(e^8x+9)^2
=72e^8x/(e^8x+9)^2
check if i mad any erroe
set u=e^(8x)
v=(e^(8x)+9)
du/dx=8e^(8x)
dv/dx=8e^8x
dy/dx=[(e^8x+9)8e^8x-e^8x(8e^8x)]/(e^8x+9)^2
dy/dx=(8e^64x+72e^8x-8e^64x]/(e^8x+9)^2
=72e^8x/(e^8x+9)^2
check if i mad any erroe
Answered by
Steve
I guess you did.
y' =
(8e^(8x))(e^(8x)+9)-(e^(8x))(8e^(8x))
-------------------------------
(e^(8x)+9)^2
= 72e^(8x)/(e^(8x)+9)^2
You can use wolframalpha.com to confirm your results:
http://www.wolframalpha.com/input/?i=derivative+e%5E(8x)%2F%5Be%5E(8x)%2B9%5D
y' =
(8e^(8x))(e^(8x)+9)-(e^(8x))(8e^(8x))
-------------------------------
(e^(8x)+9)^2
= 72e^(8x)/(e^(8x)+9)^2
You can use wolframalpha.com to confirm your results:
http://www.wolframalpha.com/input/?i=derivative+e%5E(8x)%2F%5Be%5E(8x)%2B9%5D