Asked by Jatin

A child pushes a wagon with a passenger of total mass 42 kg along a horizontal surface as fast as the
child can run, and then releases the wagon, which continues for another 16 m before stopping. The coefficient
of kinetic friction acting to slow the wagon is 0.18. What was the speed of the boy when he released the wagon?

Answers

Answered by Scott
work (energy) to stop the wagon
... w = 42 * g * .18 * 16

w equals the initial KE of the wagon
... 1/2 * 42 * v^2 = w

the speed of the boy is the same as the initial speed of the wagon
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions