Asked by Rebby
In rectangle ABCD, AD=BC=5units. Diagnals AC and BD, each of length 10 units, intersect at E. What is the degree measure of angle AEB?
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Answers
Answered by
Steve
look at the diagram. Drop a line from E to AB. E is in the center of the rectangle, so if angle AEB=θ,
tan(θ/2) = (10/2) / (5/2) = 2
θ/2 = 63.4°
θ = 126.8°
tan(θ/2) = (10/2) / (5/2) = 2
θ/2 = 63.4°
θ = 126.8°
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