Asked by Gabriel
3x-2y=1 and 2x+y=-4
Answers
Answered by
PsyDAG
Multiply second equation by 2.
4x + 2y = -8
3x - 2y = 1
Add the two equations to solve for x. Insert x into one of the equations to solve for y.
4x + 2y = -8
3x - 2y = 1
Add the two equations to solve for x. Insert x into one of the equations to solve for y.
Answered by
Reiny
I assume you are solving?
from the 2nd:
y = -2x-4
sub into the first
3x - 2(-2x - 4) = 1
3x + 4x + 8 = 1
7x = -7
x = -1
back into y = -2x - 4
y = -2(-1) - 4 = -2
x = -1 , y = -2
from the 2nd:
y = -2x-4
sub into the first
3x - 2(-2x - 4) = 1
3x + 4x + 8 = 1
7x = -7
x = -1
back into y = -2x - 4
y = -2(-1) - 4 = -2
x = -1 , y = -2
Answered by
Bosnian
Rearange your equations.
3 x - 2 y = 1 Multiply both sides by 2
6 x - 4 y = 2
2x + y = - 4 Multiply both sides by 3
6 x + 3 y = - 12
6 x - 4 y = 2
-
6 x + 3 y = - 12
______________
6 x - 6 x - 4 y - 3 y = 2 - ( - 12 )
0 - 7 y = 2 + 12
- 7 y = 14 Divide both sides by - 7
y = 14 / - 7
y = - 2
Put this value into equation:
3 x - 2 y = 1
3 x - 2 * ( - 2 ) = 1
3 x + 4 = 1 Subtract 4 to both sides
3 x + 4 - 4 = 1 - 4
3 x = - 3 Divide both sides by 3
x = - 3 / 3
x = - 1
The solutions are x = - 1 and y = - 2
3 x - 2 y = 1 Multiply both sides by 2
6 x - 4 y = 2
2x + y = - 4 Multiply both sides by 3
6 x + 3 y = - 12
6 x - 4 y = 2
-
6 x + 3 y = - 12
______________
6 x - 6 x - 4 y - 3 y = 2 - ( - 12 )
0 - 7 y = 2 + 12
- 7 y = 14 Divide both sides by - 7
y = 14 / - 7
y = - 2
Put this value into equation:
3 x - 2 y = 1
3 x - 2 * ( - 2 ) = 1
3 x + 4 = 1 Subtract 4 to both sides
3 x + 4 - 4 = 1 - 4
3 x = - 3 Divide both sides by 3
x = - 3 / 3
x = - 1
The solutions are x = - 1 and y = - 2
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