Asked by drwls
The stored potential energy in the trampoline at maximum compression, (1/2) k X^2, equals the gravitational potential energy at maximum height, M g H. (Kinetic energy is zero in both cases)
X = 0.5 m
g = 9.8 m/s^2
H = 2.5 m
k = the spring constant.
Solve for k.
k = 2MgH/X^2
A 115 kg man is jumping on a trampoline. If the trampoline is compressed .5 meters and the maximum height is 2.5 meters above the trampoline, what is the spring constant?
X = 0.5 m
g = 9.8 m/s^2
H = 2.5 m
k = the spring constant.
Solve for k.
k = 2MgH/X^2
A 115 kg man is jumping on a trampoline. If the trampoline is compressed .5 meters and the maximum height is 2.5 meters above the trampoline, what is the spring constant?
Answers
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.