Solve w= (va)/(r^2+a^2) for a.

Question

I applied the quadratic formula

a= (v/w +- sqrt (v^2/w^2 - 4*(-wr^2)) /2

and I have the answer as a= (v+/- sqrt[v^2+4w^2r^2]/w is this right?

Answer 1

No.

Answer 2

my quadratic was
wa^2 - va + wr^2 = 0

then a = (v ±√(v^2 - 4w^2r^2)/(2w)

You were close

Answer 3

Thanks