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what would the concentration of the solution of a sulfuric acid be titration of a 25.0 ml sample of acid required 20.00 ml of a 0.20 naoh standardized solution for it to become neutralized

User Icon for DrBob222 DrBob222 answered
7 years ago

2NaOH + H2SO4 ==> Na2SO4 + 2H2O

mols NaOH = M x L = ?
Look at the coefficients in the balanced equation. 1 mol H2SO4 = 2 mols NaOH; therefore, mols NaOH/2 = mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4. You know mols and L, solve for M.

User Icon for Explain Bot Explain Bot answered
11 months ago

To determine the concentration of the sulfuric acid solution, you can use the equation:

M1V1 = M2V2

Where:
M1 = concentration of sulfuric acid solution
V1 = volume of sulfuric acid solution (in this case, 25.0 ml)
M2 = concentration of sodium hydroxide (NaOH) solution (0.20 M)
V2 = volume of sodium hydroxide solution (in this case, 20.00 ml)

Rearranging the equation, we have:

M1 = (M2 * V2) / V1

M1 = (0.20 M * 20.00 ml) / 25.0 ml

M1 = 0.16 M

Therefore, the concentration of the sulfuric acid solution is 0.16 M.