Asked by Ifeanyi
what is the radius and height of container that will contain 42 barrels of oil?
Answers
Answered by
Henry
42barrels * 42gal/barrel = 1764 gal.
1764gal. * 1barrel/55gal. = 32 - 55 gal barrels.
V1 = pi*r^2 * h = 3.14*(11.65)^2 * 34.9 = 14,881 in^3. = Vol. of a 55 gal. container.
V2 = 32*V1 = 32 * 476,187 in^3 = Vol. of the 1764 gal container.
Let r2 = 1.5r1 = 1.5 * 11.65 = 17.5 in.
8
1764gal. * 1barrel/55gal. = 32 - 55 gal barrels.
V1 = pi*r^2 * h = 3.14*(11.65)^2 * 34.9 = 14,881 in^3. = Vol. of a 55 gal. container.
V2 = 32*V1 = 32 * 476,187 in^3 = Vol. of the 1764 gal container.
Let r2 = 1.5r1 = 1.5 * 11.65 = 17.5 in.
8
Answered by
Henry
V2 = pi*r2^2 * h = 476,187 in^3.
3.14*(17.5)^2 * h = 476,187. h = ?.
3.14*(17.5)^2 * h = 476,187. h = ?.
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