Question
please help me with this question. I just can't figure it out.
A cylindrical jar of radius 6cm contains water. How many iron solid spheres each of radius 1.5cm are required to immerse into the jar to raise the level of water by 2cm?
A cylindrical jar of radius 6cm contains water. How many iron solid spheres each of radius 1.5cm are required to immerse into the jar to raise the level of water by 2cm?
Answers
Volume of water rise = π(6^2)(2) = 72π
volume of 1 sphere = (4/3)π(1.5)^3 = 4.5π
number of spheres that caused the rise
= 72π/4.5π
= 72/4.5
= 16
volume of 1 sphere = (4/3)π(1.5)^3 = 4.5π
number of spheres that caused the rise
= 72π/4.5π
= 72/4.5
= 16
Related Questions
nine solid metal spheres, each of radius 2 cm, are dropped into a cylinder partly filled with water....
A cylindrical bucket with base 15 cm with water upto a height of 20 cm a heavy iron spherical ball o...
Eight solid iron spheres are dropped into a cylindrical can of diameter 24cm containing water. If th...
A solid cube of side 8cm is dropped into a cylindrical tank of radius 7cm.calculate the rise in the...