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Find the coordinates of a point on the curve y=6-x^2 at which the tangent of the curve at the point is perpendicular to the line y=1/4x+1.

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The line y=1/4x+1 has a slope of 1/4
So the perpendicular has a slope of -4

y = 6 - x^2
dy/dx = -2x

set -2x = -4 , and solve, then use your grade 9 method of finding the equation of the tangent

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