Question

80.0 ml of 1.50 M lead (IV) acetate is added to a 65.5 ml solution of 1.25 potassium chloride. 5.84 grams precipitate are collected. what is the percent yield? Calculate the concentrations of all ions remaining in solution.

Okay so I know you have to convert to moles of each compound, but I'm really not sure of anything else or how to even set the problem up....
Check your post. Are you sure that is lead(IV) acetate and not lead(II) acetate. The ppt will be lead(II) chloride, PbCl2, and not PbCl4.

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