Asked by kelvin
                Joseph deposited a certain amount of money.He earned one over nine of its principal at the number of years equal to the rate provided.Find the interest rate provided.**i need your help guys+++
            
            
        Answers
                    Answered by
            Steve
            
    (1+r/100)^r = 1/9
no real solutions. Let's try simple interest:
(r/100)*r = 1/9
r^2 = 100/9
r=10/3 = 3.33%
    
no real solutions. Let's try simple interest:
(r/100)*r = 1/9
r^2 = 100/9
r=10/3 = 3.33%
                    Answered by
            Reiny
            
    let's take $100
interest earned = 100/9
let the rate be r
then the number of years = r
100(r/100)(r) = 100/9
r^2 = 100/9
r = 10/3 = 3 1/3 % for 3 1/3 years
in general:
amount invested --- x
interest earned ---- x/9
rate ----- y/100
time ---- y
I = PRT
x(y/100)(y) = x/9
y^2 = 100/9
y = 10/3 , just like above
    
interest earned = 100/9
let the rate be r
then the number of years = r
100(r/100)(r) = 100/9
r^2 = 100/9
r = 10/3 = 3 1/3 % for 3 1/3 years
in general:
amount invested --- x
interest earned ---- x/9
rate ----- y/100
time ---- y
I = PRT
x(y/100)(y) = x/9
y^2 = 100/9
y = 10/3 , just like above
                    Answered by
            kelvin
            
    thanks for your solutions @steve and reiny
    
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