Solve: x^2 +8x </=9.

Question

How would I solve this?

Answer 1

First solve x^2 +8x -9 = 0
(x+9)(x-1) = 0
The solutions are x = 1 and -9
In the region -9 < x < 1, x^2 + 8x <9

Answer 2

Thanks just to make sure I have the problem as x^2+8x less than or equal to 9.

Answer 3

In that case -9 </= x </= 1 is the solution