Asked by Mohamed
Horizantal limit of (6x^3-8x^2-6x)/(3-11x-8x^3)
Answers
Answered by
bobpursley
multiply numerator and denominator by 1/x^3
lim= (6-8/x -6/x^2)/(3/x^3-11/x^2-8)
as x>>>inf, the limit is -3/4
lim= (6-8/x -6/x^2)/(3/x^3-11/x^2-8)
as x>>>inf, the limit is -3/4
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