Question

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Q:
A body of mass 10 kg is moving over a smooth surface, whose equation of motion is given by the relation. s = 5t + 2t² where (s) is in metres and (t) in seconds. Find the magnitude of force responsible for the motion.

Thank you Advance...;;
10N
50N
s=5t+2t²m
v=5+4tm/s
a=5m/s²
Given:
m=10kg
So,F=ma
F=10*5
F=50N
s=5t+2t²m
v=5+4tm/s
a=4m/s²
Given:
m=10kg
So,F=ma
F=10*4
F=40N
s=5t+2t²m
v=5+4tm/s
a=4m/s²
Given:
m=10kg
So,F=ma
F=10*4
F=40N

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