Asked by Priyanka

A particle accelerates from rest at a constant rate for some time and attains a velocity of 8 meter per second. Afterwards it decelerates with the consent rate and comes to rest. If the total time taken is 4 second then what is the total distance covered by the particle?
Answered by bobpursley
average speed-4m/s

distance= avgspeed*time=4m/s*4s=16m
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