Asked by Priyanka
A particle accelerates from rest at a constant rate for some time and attains a velocity of 8 meter per second. Afterwards it decelerates with the consent rate and comes to rest. If the total time taken is 4 second then what is the total distance covered by the particle?
Answers
Answered by
bobpursley
average speed-4m/s
distance= avgspeed*time=4m/s*4s=16m
distance= avgspeed*time=4m/s*4s=16m