let a_i = 2^i


20
Find Σ a_(i+1)-a_i
i=1

1 answer

Note the sum. You have

a2-a1 + a3-a2 + a4-a3 + ... + a21-a20
= a21-a1
= 2^21 - 2^1

There's really no reason to write the sum as you did. Since you know a_i explicitly, it would be better just to say

20
Σ 2^(i+1)-2^i
i=1
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