Asked by Jamie
Find the formula of
n
Σ (j+3)(j-4)
j=1
I have gotten to
n(n+1)(2n+1)/6 - n(n+1)/2 - 12n
How do I simplify it from there?
n
Σ (j+3)(j-4)
j=1
I have gotten to
n(n+1)(2n+1)/6 - n(n+1)/2 - 12n
How do I simplify it from there?
Answers
Answered by
Steve
see your other post. Repeating it does no one any good.
Don't forget your Algebra I now that you're taking Calculus!
Don't forget your Algebra I now that you're taking Calculus!
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