a) Elastic P.E. = (1/2) k X^2, where
k = 490 N/m and X = 0.400 m
b) Set Elastic P.E = (1/2) M v^2 and solve for V.
kX^2 = mV^2
V = X sqrt (k/m)
An archer pulls the bowstring back for a distance of 0.400 m before releasing the arrow. The bow and string act like a spring whose spring constant is 490 N/m.
(a) What is the elastic potential energy of the drawn bow?
(b) The arrow has a mass of 0.0300 kg. How fast is it traveling when it leaves the bow?
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