Asked by maths
An ac source of 50v,100÷πHz is connected in
series with an inductor of inductance L ad a
resistor of resistance R.the current in the circuit
is 2A ad p.d. across L and R are 30v ad 40v
respectively
1) calc d average power dissipated 2) calc d power factor in the circuit
series with an inductor of inductance L ad a
resistor of resistance R.the current in the circuit
is 2A ad p.d. across L and R are 30v ad 40v
respectively
1) calc d average power dissipated 2) calc d power factor in the circuit
Answers
Answered by
Henry
1. The resistance of the inductor is assumed to be zero.
P = Vr*I = 40 * 2 = 80 Watts.
2. pf = Cos A = Vr/E = 40/50 = 0.8.
P = Vr*I = 40 * 2 = 80 Watts.
2. pf = Cos A = Vr/E = 40/50 = 0.8.
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