Asked by Brian
At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at the rate of 10 cubic feet per minute. The diameter of the base of the cone is approx imately three times the altitude. At what rate is the height of the pile changing when it is 15 feet high?
Answers
Answered by
Reiny
let the height be h ft
then diameter = 3h ft, and the radius is 3h/2
V = (1/3)π r^2 h
= (1/3)π (9h^2/4)(h) = (3/4)π h^3
dV/dt = (9/4)π h^2 dh/dt
when h = 15, dV/dt = 10
10 = (9/4)π (15) dh/dt
dh/dt = 40/(135π) ft/s
= 8π/27 ft/s
then diameter = 3h ft, and the radius is 3h/2
V = (1/3)π r^2 h
= (1/3)π (9h^2/4)(h) = (3/4)π h^3
dV/dt = (9/4)π h^2 dh/dt
when h = 15, dV/dt = 10
10 = (9/4)π (15) dh/dt
dh/dt = 40/(135π) ft/s
= 8π/27 ft/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.