Asked by Alexis
Can you check the following problems?
4. x^2 - 10x +25 = 9
x^2 - 10x + (25 -9) = 9 - 9
x^2 - 10x + 16 = 0
(x - 8)(x-2) = 0
x - 8 = 0, x - 2 = 0
x = 8, x = 2
5. x^2 - 6x + 9 = 49
x^2 - 6x + ( 9 - 49) = 49 - 49
x^2 - 6x - 40 = 0
(x -10)(x + 4) = 0
x - 10 = 0, x +4 = 0
x = 10, x = -4
6. x^2 + 2x + 1 = 64
x^2 + 2x + (1 - 64) = 64 - 64
x^2 + 2x -63 = 0
(x +9)(x - 7) = 0
x + 9 = 0, x - 7 = 0
x = -9, x = 7
7. x^2 - 18x + 81 = 24
x^2 - 18x + (81 - 24) = 24 - 24
x^2 - 18x + 57 = 0
(x - 19)(x - 3)
Not sure what to do next. 3 & 19 doesnt give 18 for middle term.
8. x^2 + 12x + 36 = 75
x^2 + 12x + (36 - 75) = 75 -75
x^2 + 12x - 39 = 0
Not sure what's next. 3 & 13 doesn't give 12 for middle term.
I'm not about these below either.
9. (x - 1/2)^2 = 1
√(x - 1/2)^2 = +- √1
x - 1/2 = +- 1
x - 1/2 = 1, x -1/2 = -1
x = 3/2, -1/2
10. (x - 3/2)^2 = 7/4
√(x - 3/2)^2 = +- √7/√4
x - 3/2 = +- √7/2
x - 3/2 = +- √7/2
x = 3/2 +- √7/2 or
x = (3 +- √7)/2
11. (x + 5/2)^2 = 15/4
√(x + 5/2)^2 = +- √15/√4
x + 5/2 = +- √15/2
x = -5/2 +- √15/2 or
x = (-5 +- √15)/2
12. 2x^2 = 5
2x^2/2 = 5/2
x^2 = 5/2
√x^2 = +- √5/√2
x = +- √5/√2
13. (x - 1/2)^2 = 3/2
√(x - 1/2)^2 = +- √3/√2
x - 1/2 = +- √3/2
x = 1/2 +- √3/√2
14. (x-3/5)^2 = 4/5
√(x - 3/5)^2 = +- √4/√5
x - 3/5 = 2√5
x = 3/5 +- 2√5 or
x = (3 +- 2√5)/5
15. 3(x + 7/3)^2 = 1
[3(x + 7/3)^2)]/3 = 1/3
(x + 7/3)^2 = 1/3
√(x + 7/3)^2 = +- √1/√3
x + 7/3 = +- √3
x = -7/3 +- √3 or
x = (-7 +- √3)/3
4. x^2 - 10x +25 = 9
x^2 - 10x + (25 -9) = 9 - 9
x^2 - 10x + 16 = 0
(x - 8)(x-2) = 0
x - 8 = 0, x - 2 = 0
x = 8, x = 2
5. x^2 - 6x + 9 = 49
x^2 - 6x + ( 9 - 49) = 49 - 49
x^2 - 6x - 40 = 0
(x -10)(x + 4) = 0
x - 10 = 0, x +4 = 0
x = 10, x = -4
6. x^2 + 2x + 1 = 64
x^2 + 2x + (1 - 64) = 64 - 64
x^2 + 2x -63 = 0
(x +9)(x - 7) = 0
x + 9 = 0, x - 7 = 0
x = -9, x = 7
7. x^2 - 18x + 81 = 24
x^2 - 18x + (81 - 24) = 24 - 24
x^2 - 18x + 57 = 0
(x - 19)(x - 3)
Not sure what to do next. 3 & 19 doesnt give 18 for middle term.
8. x^2 + 12x + 36 = 75
x^2 + 12x + (36 - 75) = 75 -75
x^2 + 12x - 39 = 0
Not sure what's next. 3 & 13 doesn't give 12 for middle term.
I'm not about these below either.
9. (x - 1/2)^2 = 1
√(x - 1/2)^2 = +- √1
x - 1/2 = +- 1
x - 1/2 = 1, x -1/2 = -1
x = 3/2, -1/2
10. (x - 3/2)^2 = 7/4
√(x - 3/2)^2 = +- √7/√4
x - 3/2 = +- √7/2
x - 3/2 = +- √7/2
x = 3/2 +- √7/2 or
x = (3 +- √7)/2
11. (x + 5/2)^2 = 15/4
√(x + 5/2)^2 = +- √15/√4
x + 5/2 = +- √15/2
x = -5/2 +- √15/2 or
x = (-5 +- √15)/2
12. 2x^2 = 5
2x^2/2 = 5/2
x^2 = 5/2
√x^2 = +- √5/√2
x = +- √5/√2
13. (x - 1/2)^2 = 3/2
√(x - 1/2)^2 = +- √3/√2
x - 1/2 = +- √3/2
x = 1/2 +- √3/√2
14. (x-3/5)^2 = 4/5
√(x - 3/5)^2 = +- √4/√5
x - 3/5 = 2√5
x = 3/5 +- 2√5 or
x = (3 +- 2√5)/5
15. 3(x + 7/3)^2 = 1
[3(x + 7/3)^2)]/3 = 1/3
(x + 7/3)^2 = 1/3
√(x + 7/3)^2 = +- √1/√3
x + 7/3 = +- √3
x = -7/3 +- √3 or
x = (-7 +- √3)/3
Answers
Answered by
Steve
#7: x^2 - 18x + 57 = 0
Looks like the quadratic formula is what you'll need:
x = 9±√24
Or, you could complete the square, as was done in the following problems:
x^2 - 18x + 57 = 0
x^2 - 18x + 81 = 24
(x-9)^2 = ±√24
x = 9±√24
The rest look good, except for a few typos.
Looks like the quadratic formula is what you'll need:
x = 9±√24
Or, you could complete the square, as was done in the following problems:
x^2 - 18x + 57 = 0
x^2 - 18x + 81 = 24
(x-9)^2 = ±√24
x = 9±√24
The rest look good, except for a few typos.
Answered by
Anonymous
Okay. thanks! It was confusing to me. I'll double check them for typos and look up quadratic formula.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.