A 1070 kg hybrid car pushes a 2140 kg Jeep that has died on railroad tracks. If the wheels of the hybrid car push against the ground with 5890 N of force, what is the magnitude of the force between the hybrid car and the Jeep? Assume there is no rolling friction.

asked by 2FUN

8 years ago

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1 answer

F = m a
5890 = (1070+2140) a
a = 5890/(1070+2140)

then
Fjeep = 2140 a

answered by Damon

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1

Question

A 1070 kg hybrid car pushes a 2140 kg Jeep that has died on railroad tracks. If the wheels of the hybrid car push against the ground with 5890 N of force, what is the magnitude of the force between the hybrid car and the Jeep? Assume there is no rolling friction.

1 answer

F = m a
5890 = (1070+2140) a
a = 5890/(1070+2140)

then
Fjeep = 2140 a

Damon · Answer

F = m a 5890 = (1070+2140) a a = 5890/(1070+2140) then Fjeep = 2140 a