The mid-point of the straight line joining A(4,-3), B(6,-2) is located at C.
(a) Calculate the coordinates of C.
(b) Verify your result by calculating the distances AC and BC and showing they are equal.
I HAVE COMPLETED A BUT CAN'T DO DO B!!!!
3 answers
try to use distance formula, then compare their distance
Do I have to do part a too ?
-2 + -3 = -5
-5/2 = -2.5 which is y of C
4 ) 6 = 10
10/5 = 5 which is x of C
so
C(5, -2.5)
now AC
dx = 5-4 = 1
dy = -2.5 - -3 = .5
d^2 = 1+.25
now CB
dx = 6 -5 = 1
dy = -2 - -2.5 = .5
d^2 = 1 + .25 the same
-5/2 = -2.5 which is y of C
4 ) 6 = 10
10/5 = 5 which is x of C
so
C(5, -2.5)
now AC
dx = 5-4 = 1
dy = -2.5 - -3 = .5
d^2 = 1+.25
now CB
dx = 6 -5 = 1
dy = -2 - -2.5 = .5
d^2 = 1 + .25 the same