Asked by IZAAK SiDney Dunkan
A 30 kg student pushes a 20kg box on frictionless surface. If student accelerates at 0.8m/s^2(N),what is acceleration of bix. now why does the box acceerate towards south, if it is being pushed north should it not move north.
Answers
Answered by
Damon
Before the push, the momentum of the system was zero
so since there is no EXTERNAL force on the student/box system,
After the push the total momentum of the system is zero.
Therefore
If the student goes North
then
The box goes South
if north is +
.8 (30) + v (20) = 0
v = -.8(30/20)
so since there is no EXTERNAL force on the student/box system,
After the push the total momentum of the system is zero.
Therefore
If the student goes North
then
The box goes South
if north is +
.8 (30) + v (20) = 0
v = -.8(30/20)
Answered by
Damon
PS
Perhaps you missed that word "frictionless"
Do not think you are pushing that box along a hockey rink. That requires friction and cleats on your shoes if on ice.
If no cleats, if the box goes one way you go the other :)
Perhaps you missed that word "frictionless"
Do not think you are pushing that box along a hockey rink. That requires friction and cleats on your shoes if on ice.
If no cleats, if the box goes one way you go the other :)
Answered by
asdfghj
The answer would be 1.2 m/s^2.
Since the student is pushing against the box, the amount of force they are using is equivalent to the amount of force the box is pushing back (As explained by Newton's third law of motion). Therefore, you first have to find the amount of force the student is using, and then set that equal to the mass of the box to find its acceleration.
F(of the student)=ma
=30(.8)
=24N
F(student)=f(box)
24N=ma
24=20(a)
acceleration of the box= 24/20= 1.2 m/s^2
Since the student is pushing against the box, the amount of force they are using is equivalent to the amount of force the box is pushing back (As explained by Newton's third law of motion). Therefore, you first have to find the amount of force the student is using, and then set that equal to the mass of the box to find its acceleration.
F(of the student)=ma
=30(.8)
=24N
F(student)=f(box)
24N=ma
24=20(a)
acceleration of the box= 24/20= 1.2 m/s^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.