Asked by Vicky
HOW MANY ATOMS OF OXYGEN ARE PRESENT IN 8.8G OF CARBON(IV)OXIDE
Answers
Answered by
bobpursley
CO2.
moles of CO2=8.8g/44g
moles of O=2*8.8/44
atoms O= avagnumber*moles of O
moles of CO2=8.8g/44g
moles of O=2*8.8/44
atoms O= avagnumber*moles of O
Answered by
Sania
One only
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