Question
HOW MANY ATOMS OF OXYGEN ARE PRESENT IN 8.8G OF CARBON(IV)OXIDE
Answers
bobpursley
CO2.
moles of CO2=8.8g/44g
moles of O=2*8.8/44
atoms O= avagnumber*moles of O
moles of CO2=8.8g/44g
moles of O=2*8.8/44
atoms O= avagnumber*moles of O
Sania
One only