How much heat was generated.
3947.0 kJ/mol x (1.311/16.59) = q
Then q = Ccal*delta T
Substitute and solve for Ccal.
At constant volume, the heat of combustion of a particular compound is –3947.0 kJ/mol. When 1.311 g of this compound (molar mass = 136.58 g/mol) was burned in a bomb calorimeter, the temperature of the calorimeter (including its contents) rose by 4.343 °C. What is the heat capacity (calorimeter constant) of the calorimeter?
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