2 answers
(click or scroll down)
Vo = 0.6m/s[20o].
Range = Vo^2*sin(2A)/g.
Range = 0.6^2*sin(40)/9.8 =
Range = Vo^2*sin(2A)/g.
Range = 0.6^2*sin(40)/9.8 =
R = (v^2 * sin(2θ)) / g
Where:
- v is the initial velocity of the frog (0.6 m/s)
- θ is the launch angle (20 degrees)
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
First, let's convert the launch angle from degrees to radians, as the trigonometric functions in most programming languages work with radians. To convert degrees to radians, use the following equation:
radians = degrees * (Ï€/180)
For our case, the launch angle in radians (θ_radians) will be:
θ_radians = 20 * (π/180)
Now we can plug in the values into the range equation:
R = (0.6^2 * sin(2 * θ_radians)) / 9.8
Note: "^" denotes exponentiation.
Let's calculate the value of R.