Asked by Mohammed

use implicit differentiation to find dy/dx.
xy^2+4y^3=x-2y
Answered by Madeline
x=-4y^3-2y/y^2-1
Answered by Reiny
xy^2+4y^3=x-2y
x(2y)dy/x + y^2 + 12y^2 dy/dx = 1 - 2dy/dx
dy/x(2xy + 12y^2 + 2) = 1 - y^2

dy/dx = (1 - y^2)/(2xy + 12y^2 + 2)
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