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Original Question
Find the perimeter of the triangle whose certified are the following specified points in the plane (5,-1) (-9,3) and (0,1Asked by cindy
Find the perimeter of the triangle whose vertices are the following specified points in the plane? (0,-3), (-2,1) and (-4,6)
Answers
Answered by
David
To find the distance between two points (x1, y1) and (x2, y2), all that you need to do is use the coordinates of these ordered pairs and apply the formula:
Distance = √((x2 − x1)^2 + (y2 − y1)^2)
So, in using this formula, we find that:
1. The distance between (0, -3) & (-2, 1) is √(20)
2. The distance between (-2, 1) & (-4, 6) is √(29)
3. The distance between (0, -3) & (-4, 6) is √(97)
Thus, the perimeter is the sum of these three distances.
√(20) + √(29) + √(97) = roughly 19.706
Distance = √((x2 − x1)^2 + (y2 − y1)^2)
So, in using this formula, we find that:
1. The distance between (0, -3) & (-2, 1) is √(20)
2. The distance between (-2, 1) & (-4, 6) is √(29)
3. The distance between (0, -3) & (-4, 6) is √(97)
Thus, the perimeter is the sum of these three distances.
√(20) + √(29) + √(97) = roughly 19.706