Question

Standardization of iodine solution was prepared using 10.0 mL of a standard, 1.00 mg/mL, ascorbic acid solution. Titration with the iodine solution required 35.80 mL to reach the end point. What is the molarity of the iodine solution?

Answer 1

ascorbic acid + I2 ==> 2I^- + dehydroascorbic acid

mg ascorbic acid = 10 mL x 1 mg/mL = 10 mg.
mols ascorbic acid = 0.01 g/molar mass ascorbic acid
Using the coefficients in the blanced equation, convert mols ascorbic acid to mols I2.
Then M I2 = mols I2/L I2