Question
Use differentials to approximate the value of the 4th root of 82
How do I even start?
How do I even start?
Answers
Steve
let y = ∜x
dy = 1/(4∜x^3) dx
y(81) = 3
let dx=1
dy = 1/(4*27) (1) = 1/108
∜82 ≈ 3 + 1/108 = 3.009259
actually, ∜82 = 3.009216
dy = 1/(4∜x^3) dx
y(81) = 3
let dx=1
dy = 1/(4*27) (1) = 1/108
∜82 ≈ 3 + 1/108 = 3.009259
actually, ∜82 = 3.009216