If ADB is an altitude, it is perpendicular to BC, and angle ADB is 90 degrees. Therefore
2x^2 + 40 = 90 and x = 5
BC = BD + DC = 15x + 12
In acute triangle ABC, segment AD is an altitude, the measure of angle ADB=2x^2+40, BD=9x-3, and DC=6x+15. Find BC.
2 answers
This is the fourth question I have answered for you in the last hour.
It is about time you show me some of your work.
Clue for this one:
doesn't the altitude AD hit the base BC at a right angle ??
This one works out sooooo nicely, let me know what you got.
It is about time you show me some of your work.
Clue for this one:
doesn't the altitude AD hit the base BC at a right angle ??
This one works out sooooo nicely, let me know what you got.
0 answers