Asked by KAdila
                For what value of 'K' the number 3K + 2, 4K +3 and 6K - 1 are the consecutive terms of an A.P.
            
            
        Answers
                    Answered by
            Steve
            
    you need a common difference, so
(4k+3)-(3k+2) = (6k-1)-(4k+3)
    
(4k+3)-(3k+2) = (6k-1)-(4k+3)
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