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Asked by KAdila

For what value of 'K' the number 3K + 2, 4K +3 and 6K - 1 are the consecutive terms of an A.P.
9 years ago

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Answered by Steve
you need a common difference, so

(4k+3)-(3k+2) = (6k-1)-(4k+3)
9 years ago
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For what value of 'K' the number 3K + 2, 4K +3 and 6K - 1 are the consecutive terms of an A.P.

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