Asked by Caden
A rocket leaves the launch pad heading straight up with a constant acceleration of 60 m/s^2 \. its initial stage booster runs out in 25 seconds. How high is the rocket?
Answers
Answered by
bobpursley
hf=vi*t+1/2 at^2
hf=1/2 *60*25^2
I am assuming the acceleration given is NET acceleration upward
hf=1/2 *60*25^2
I am assuming the acceleration given is NET acceleration upward
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