Asked by Kevin
You push a 1kg block against a spring with spring constant k = 100 Nmon a horizontal table top. The spring is compressed to 0.2m away from its relaxed length, and then the block is released. If the horizontal table top has a
coefficient of kinetic friction of 0.2, how much further past the end of the spring does the block go before coming to rest?
coefficient of kinetic friction of 0.2, how much further past the end of the spring does the block go before coming to rest?
Answers
Answered by
Damon
energy stored in spring = (1/2) k x^2
= (1/2)(100)(.04)
work done by friction
= mu m g *d
so
50*.04 = .2 * 1 *9.81* d
solve for d
= (1/2)(100)(.04)
work done by friction
= mu m g *d
so
50*.04 = .2 * 1 *9.81* d
solve for d
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