Asked by Wasim
Ball 1 initially travels with a velocity of u m/s.Ball 2 is stationery and has a mass of 0.2kg and this collision lasts for 0.1 s.Afterwards both balls move in the direction of ball 1's initial velocity. Each ball has a different final velocity.
During the collision a force of -6N is exerted on ball 1 by ball 2 calculate the velocity of ball 2 after the collision.
During the collision a force of -6N is exerted on ball 1 by ball 2 calculate the velocity of ball 2 after the collision.
Answers
Answered by
bobpursley
Hmmm. If -6N was exerted on ball 1, then 6N was exerted on ball2
6*.1=.2w
w=3m/s
6*.1=.2w
w=3m/s
Answered by
Liam Joseph
Since p=mv, the momentum for the ball2 initially is 0.2 * 0 = 0 kg m/s.
It is stated that -6N of force was exerted by ball2 on ball1, so because of Newton's third law stating that there is always a force acting in the equal and opposite direction, we know that 6N has been acted by ball1 on ball2.
Since F=(mv-mu)/t, we can substitute some values in:
6=(mv-mu)/0.1
0.6=mv-mu
mv-mu is the change in momentum, so 0.6 is the change in momentum.
Using the formula p=mv again, we can calculate the final velocity of ball2 now.
p=mv
0.6=0.2v
0.6/0.2=v
v=3 m/s
It is stated that -6N of force was exerted by ball2 on ball1, so because of Newton's third law stating that there is always a force acting in the equal and opposite direction, we know that 6N has been acted by ball1 on ball2.
Since F=(mv-mu)/t, we can substitute some values in:
6=(mv-mu)/0.1
0.6=mv-mu
mv-mu is the change in momentum, so 0.6 is the change in momentum.
Using the formula p=mv again, we can calculate the final velocity of ball2 now.
p=mv
0.6=0.2v
0.6/0.2=v
v=3 m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.