Asked by cindy
                Calculate to four decimal places the mass of purely dry MgCO3(Magnesium Carbonate) required to make 1L of a 1000 ppm Mg stock solution.
            
            
        Answers
                    Answered by
            DrBob222
            
    A good factor to remember is
1 ppm = 1 mg/L so 1000 ppm would be 1000 mg/L
So you want1000 mg (that's 1 gram) MgCO3 in a L of solution.
    
1 ppm = 1 mg/L so 1000 ppm would be 1000 mg/L
So you want1000 mg (that's 1 gram) MgCO3 in a L of solution.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.