Question
a ball thrown vertically upward from the ground,hit the ground after 4seconds,calculate the maximum height reach by the ball during the jorney
Answers
time up equals time down
h = 1/2 g t^2 = 4.9 m/s^2 * (2 s)^2
h = 1/2 g t^2 = 4.9 m/s^2 * (2 s)^2
I don't know pls can u fully explain the answer
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