Asked by iselle

the sum of 2+4+6...800
Answered by Steve
this is just 2(1+2+...+400)
So, there are 400 terms.

S400 = 400/2 (2+800)

Or, you probably know that
1+2+3+...+n =n(n+1)/2

So, your sum is 2* 400*401/2
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