Asked by RACHEL
Factor the trigonometric expression. There is more than one correct form of the answer.
cot^2 x + csc x − 19
NOT SURE WHETHER TO REPLACE THE COT WITH COS^2X/SIN^2X THEN CSCX TO 1/SINX?
cot^2 x + csc x − 19
NOT SURE WHETHER TO REPLACE THE COT WITH COS^2X/SIN^2X THEN CSCX TO 1/SINX?
Answers
Answered by
Steve
cot^2 = csc^2 - 1
use that and it factors easily.
use that and it factors easily.
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