Asked by Vijay
Differentiation with respect to x' of the following function:
(1) (x2-5x+6) (x-3)
(1) (x2-5x+6) (x-3)
Answers
Answered by
Reiny
did you mean
y = (x^2 - 5x+6)(x-3) ?
For this one, I would have actually expanded it.
y = x^3 - 3x^2 - 5x^2 + 15x + 6x - 18
= x^3 - 8x^2 + 21x - 18
dy/dx = 3x^2 - 16x + 21
or .... by the product rule:
dy/dx = (x^2 - 5x + 6)(1) + (2x - 5)(x-3)
= x^2 - 5x + 6 + 2x^2 - 6x - 5x + 15
= 3x^2 - 16x + 21
y = (x^2 - 5x+6)(x-3) ?
For this one, I would have actually expanded it.
y = x^3 - 3x^2 - 5x^2 + 15x + 6x - 18
= x^3 - 8x^2 + 21x - 18
dy/dx = 3x^2 - 16x + 21
or .... by the product rule:
dy/dx = (x^2 - 5x + 6)(1) + (2x - 5)(x-3)
= x^2 - 5x + 6 + 2x^2 - 6x - 5x + 15
= 3x^2 - 16x + 21
Answered by
Vijay
Thankyou sir
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