A 1.577 M solution of AgNO3 has a density of 1.220 gram per centimeter cube. What is the molality of the solution?

Answer 1

1.577 M is 1.577 mols/L solution. With density = 1.220 g/mL, then substitute volume and density to find mass of the solution.
1.577 mols AgNO3 x molar mass AgNO3 = grams AgNO3.
Then mass solution - g AgNO3 = mass solvent. Convert that to kg.
m = 1.577 mols AgNO3/kg solvent

Answer 2

0.01