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Two transformations take place, the resultant change is A(x,y) ---A''(x+4, y-^, This is a result of a reflection in the y axis...Asked by Susana
Two transformations take place, the resultant change is A(x,y) ---A''(x+4, y-6), This is a result of a reflection in the y axis followed by a _________ (translation, reflection, rotation).
I have the answer give by teacher as a "reflection, but I don't understand why or how the teacher comes out with a second reflection, please help
I have the answer give by teacher as a "reflection, but I don't understand why or how the teacher comes out with a second reflection, please help
Answers
Answered by
Steve
if you need to fix a problem, don't repost the whole thing again. Just edit your original post. Wastes time checking all the redundant posts.
Since the question specifies that there was an initial reflection, the only way to wind up with no reflection is to have a second reflection to cancel it:
A(x,y) -> A'(-x,y) -> A"(-x+4,y-6)
or
A(x,y) -> A'(x,-y) -> (x+4,-y-6)
Since the question specifies that there was an initial reflection, the only way to wind up with no reflection is to have a second reflection to cancel it:
A(x,y) -> A'(-x,y) -> A"(-x+4,y-6)
or
A(x,y) -> A'(x,-y) -> (x+4,-y-6)
Answered by
Susana
Thank you for answering, still I don't completely know how looking at A''(-x+4,y-6) you can determine there is a second reflection, I know first reflection over Y will be A' (-x,y), but do you get that the second is a reflection too and it is not a rotation.
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