Asked by Sagar Ali Joyo

The speed of sound in air is 350m/sec the frequency of the fundamental node emitted by tube length 50cm open one end is:
Answered by Anonymous
T = 0.50*4/340
do
f = 1/T = 340/2 = 170 Hz
Answered by Damon
http://www.physicsclassroom.com/class/sound/Lesson-5/Closed-End-Air-Columns
Answered by Anonymous
its one end is close so we will cosider it as closed or open i mean we have to apply the closed formula or open one
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