Asked by tish
lim x→0 of [2-cos3x-cos4x]/(x)
Answers
Answered by
Damon
as y--->0
cos y = 1 - y^2/2 + ........
numerator:
2 - 1 +(1/2)(9)x^2 -1 +(1/2)(16)x^2
0 + (25/2)x^2 oh my
now divide by x
25 x/2
goes to 0 as x goes to 0
cos y = 1 - y^2/2 + ........
numerator:
2 - 1 +(1/2)(9)x^2 -1 +(1/2)(16)x^2
0 + (25/2)x^2 oh my
now divide by x
25 x/2
goes to 0 as x goes to 0
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