Ask a New Question

Asked by Liv

Derive an identity that transforms sin(α+β+γ) into a sum of products of sines and/or cosines of the individual numbers α, β, γ.
8 years ago

Answers

Answered by Reiny
sin(α+β+γ) , I will use sin(a+b+c) for easier typing
= sin( (a+b) +c)
= sin(a+b)cos c + cos(a+b)sin c
= (sinacosb + cosasinb)(cosc) + (cosacosb - sinasinb)sinc
= sinacosbcosc + cosacoscsinb + cosacosbsinc - sinasinbsinc

now put back your α,β, and γ
8 years ago

Related Questions

How could the following transformation could be carried out. C6H5C=CH --> C6H5CH2CH20H I don't kno... What is the name of the transformers in which a single coil is used for both primary and secondary w... Derive the identity cot² A+1= csc² A Derive the identity cot² A+1= csc² A to derive this identity does it mean to change the cot^2 A... Derive the identity 1 + cot ^2 theta = csc^2 theta by dividing x^2 + y^2 = r^2 by y^2 How do you derive this identity? Cos(t)=1-sin^2(t/2) Derive this identity from the sum and difference formulas for cosine: sinasinb=1/2[cos(a-b)cos(a+b... How will the following transformation rule move a preimage? (x,y)→(−x,−y) A. It will be translat... Which of the following transformed city life in the late 1800s? Select all that apply. (1 point)...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use